Răspuns: [tex]\color{red}\Large \boxed{\bf \dfrac{7}{6}}[/tex]
Explicație pas cu pas:
[tex]\large \bf \bigg(\dfrac{3}{4} + \dfrac{2}{9} -\dfrac{\not8}{9}\cdot \dfrac{7}{\not8}\bigg):\dfrac{1}{6} =\bigg(\dfrac{3}{4} + \dfrac{2}{9} -\dfrac{7}{9}\bigg):\dfrac{1}{6}=[/tex]
[tex]\it~~[/tex]
[tex]\large \bf \bigg(\dfrac{3}{4}- \dfrac{5}{9} \bigg):\dfrac{1}{6}=\bigg(\dfrac{3\cdot9}{4\cdot9}- \dfrac{5\cdot4}{9\cdot4} \bigg)\cdot\dfrac{6}{1}=\bigg(\dfrac{27}{36}- \dfrac{20}{36} \bigg)\cdot\dfrac{6}{1}=[/tex]
[tex]\it~~[/tex]
[tex]\large \bf \dfrac{7}{36} \cdot\dfrac{6}{1}=\dfrac{7}{\not36} \cdot\dfrac{\not6}{1}=\boxed{\bf \dfrac{7}{6}}[/tex]
==pav38==
