Răspuns:
b) 64-120÷6-a=40
=64-20-a=40
=44-a=40
=-a=40-44
=-a=-4
a=4
c) 460-4×[a×(30-1)]=58
=460-4×(a×29)=58
=460-4×(29a)=58
=460-4×29a=58
=460-116a=58
=-116a=58-460
=-116a=-402
a=
[tex] \frac{201}{58} [/tex]
n)135+5000÷1000+a×44=272
=135+5+44a=272
=140+44a=272
=44a=272-140
=44a=132
=a=3
o) 832÷a+[40+8×(100÷5-90÷5)]×10=592, a= =taiat 0
=
[tex] \frac{832}{a} [/tex]
+[40+8×(20-18)]×10=592
=
[tex] \frac{832}{a} [/tex]
+(40+8×2)×10=592
=
[tex] \frac{832}{a} [/tex]
+(40+16)×10=592
=
[tex] \frac{832}{a} [/tex]
+56×10=592
=
[tex] \frac{832}{a} [/tex]
+560=592
=
[tex] \frac{832}{a} [/tex]
=592-560
=
[tex] \frac{832}{a} [/tex]
=32
=832=32a
32a=832
a=26, a= =taiat 0
a=26
