Răspuns:
9
Explicație pas cu pas:
Conditii: x>0 => x∈(0;+∞) => D=(0;+∞)
log₃x+log₉x=3
log₃x+log₃x/log₃9=3
log₃x+log₃x/2=3
(1+1/2)log₃x=3
[tex]\frac{3}{2}[/tex]log₃x=3
log₃x=6/3
log₃x=2
x=3²=>x=9 ∈ D => S={9}