Răspuns:
Sper ca te-am ajutat!!!
[tex]\it \Big(\dfrac{^{3)}1}{x}+\dfrac{2}{3x}-\dfrac{^{3)}4}{x}\Big):\Big(\dfrac{^{4)}2}{x}-\dfrac{1}{4x}+\dfrac{^{4)}2}{x}\Big)=\dfrac{3+2-12}{3x}:\dfrac{8-1+8}{4x}=\\ \\ \\ =\dfrac{-7}{3\not x}\cdot\dfrac{4\not x}{15}=-\dfrac{28}{45}[/tex]
