Răspuns:
a.
-3x+2<-7
-3x<-9
x<3 => x apartine (-infinit,3)
b.
3(x-1)>2x+9
3x-3>2x+9
x>12 =>x apartine (12,+infinit)
c.
4(3x+2)-14x>69-3(2x+3)
12x+8-14x>69-6x-9
2x+8>-6x+60|:2
x+4>-3x+30
4x>26
x>13/2 =>x apartine(13/2,+infinit)
d.
[3(x-4)-5(x+4)]/(-2)<3|*(-2)
3(x-4)-5(x+4)>-6
3x-12-5x-20>-6
-2x>-34
x<17 =>x apartine(-infinit,17)
e.
[2(1-x)+3x-5]/(-2)<1|*(-2)
2(1-x)+3x-5>-2
2-2x+3x-5>-2
x>1 =>x apartine(1,+infinit)
f.
[9-5x+2(x+3)]/(-3)<2|*(-3)
9-5x+2(x+3)>-6
9-5x+2x+6>-6
-3x>-21
x<7 =>x apartine(-infinit,7)
