Răspuns :

Alexandraceacaid

Răspuns:

Explicație pas cu pas:

[tex]\frac{1}{\sqrt{7} } *\frac{2x}{\sqrt{7} } -\frac{1}{\sqrt{7} } *5\sqrt{2} =x\\\frac{2x}{7} -\frac{5\sqrt{2} }{\sqrt{7} } =x\\\\\frac{2x}{7} -\frac{5\sqrt{14} }{7} =\frac{7x}{7\\}\\2x-5\sqrt{14} =7x\\-5\sqrt{14} =5x\\x=\frac{-5\sqrt{14} }{5} \\x=-\sqrt{14}[/tex]

Sper ca te-am ajutat!

Targoviste44id

[tex]\it \dfrac{1}{\sqrt7}\Big(\dfrac{2}{\sqrt7}x-5\sqrt2\Big)=x|_{\cdot\sqrt7}\ \Rightarrow\ \dfrac{2}{\sqrt7}x-5\sqrt2=x\cdot\sqrt7|_{\cdot\sqrt7} \Rightarrow 2x-5\sqrt{14}=7x\Rightarrow\\ \\ \\ \Rightarrow -5\sqrt{14}=7x-2x\Rightarrow -5\sqrt{14}=5x|_{:5}\Rightarrow -\sqrt{14}=x\Rightarrow x=-\sqrt{14}[/tex]

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