Răspuns :

 

[tex]\displaystyle\bf\\\frac{x}{y}=5\\\\\\\frac{5x-3y}{4y}=\frac{5x}{4y}-\frac{3y}{4y}=\frac{5}{4}\cdot\frac{x}{y}-\frac{3}{4}=\\\\=\frac{5}{4}\cdot5-\frac{3}{4}=\frac{25}{4}-\frac{3}{4}=\frac{25-3}{4}=\frac{22}{4}=\frac{11}{2}[/tex]

 

 

 

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