Răspuns :
[tex]\it \overline{abc}:\overline{bc}=4\ \ rest\ \ a \Rightarrow \overline{abc}=4\cdot\overline{bc}+a \Rightarrow 100a+\overline{bc}=4\cdot\overline{bc}+a \Rightarrow \\ \\ \Rightarrow 100a-a=4\overline{bc}-\overline{bc} \Rightarrow 99a=3\overline{bc}|_{:3} \Rightarrow 33a=\overline{bc}\ \ \ \ \ \ (*)[/tex]
[tex]\it a=1\stackrel{(*)}{\Longrightarrow}\ \overline{bc}=33 \Rightarrow b=c=3\\ \\ a=2\stackrel{(*)}{\Longrightarrow}\ \overline{bc}=66 \Rightarrow b=c=6\\ \\ a=3\stackrel{(*)}{\Longrightarrow}\ \overline{bc}=99 \Rightarrow b=c=9[/tex]
Alte valori ale cifrei a nu convin.