Răspuns:
a) 3/2 → 3 supra 2, unde / = linia de fracție
3/2 + ( 5/2) × ( 4/15) = 3/2 + (5/15) ×(4/2) = ³⁾(3/2) + ²⁾(2/3) = 9/6+4/6=13/6
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b)
5/6 + ( 1/6 )×(4/5) = ⁵⁾(5/6) + ²⁾(2/15) = 25/30 + 4/30 = 29/30
Aflăm cel mai mic multiplu comun al numitorilor 6 și 15:
6 = 2×3
15 = 3×5
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c.m.m.m.c al numerelor 6 și 15 = 2×3×5 = 30
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c)
7/5 - (2/5) × (3/2) = 7/5 - 3/5 = 4/5
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d)
10/3 - (2/3) : ( 4/5) = 5/2
= 10/3 - (2/3) × (5/4) =
= ²⁾(10/3) - 5/6 =
= 20/6 - 5/6 =
= (15/6)⁽³ =
= 5/2
