Răspuns :
a+b=15
{a,b}dp{2,3}=>a supra 2=b supra 3
egalam cu k=>a=2k si b=3k
2k+3k=15
5k=15
k=3=>a=3*2=6
b=3*3=9
{x;y}d.p.{2;3}
x/2=y/3=k
x=2k
y=3k
x+y=15
2k+3k=15
5k=15
k=3
x=6
y=9
(Nr sunt 6 si 9)
x/2=y/3=k
x=2k
y=3k
x+y=15
2k+3k=15
5k=15
k=3
x=6
y=9
(Nr sunt 6 si 9)