Răspuns:
[tex]\color{CC0000}\large\boxed{\boxed{\bf S = \dfrac{6^{2019}-1}{5}}}[/tex]
Explicație pas cu pas:
Buna!
[tex]\boxed{\bf S = 1+6+6^{2} +6^{3}+.......+6^{2018}}[/tex]
[tex]\bf S = 6^{0}+6^{1}+6^{2} +6^{3}+.......+6^{2018}~~\bigg|\cdot 6[/tex]
[tex]\bf 6S = 6^{0+1}+6^{1+1}+6^{2+1} +6^{3+1}+.......+6^{2018+1}[/tex]
[tex]\boxed{\bf 6S = 6^{1}+6^{2}+6^{3} +6^{4}+.......+6^{2019}}[/tex]
[tex]\text{\bf Scadem cele doua relatii si vom avea}[/tex]
[tex]\bf 6S-S = 6^{1}+6^{2}+6^{3} +6^{4}+....+6^{2019}-(6^{0}+6^{1}+6^{2} +6^{3}+....+6^{2018})[/tex]
[tex]\bf 5S = \not6^{1}+\not6^{2}+\not6^{3} +\not6^{4}+...\not~+6^{2019}-6^{0}-\not6^{1}-\not6^{2} -\not6^{3}-....-\not6^{2018}[/tex]
[tex]\bf 5S = 6^{2019}-6^{0}[/tex]
[tex]\bf 5S = 6^{2019}-1~~~\bigg|:5[/tex]
[tex]\color{CC0000}\large\boxed{\boxed{\bf S = \dfrac{6^{2019}-1}{5}}}[/tex]
PS: Daca esti pe telefon, te rog sa glisezi spre dreapta pentru a vedea rezolvarea completa
==pav38==
