Răspuns:
Q=(C,vas+ m,solxc,sol)Δt
ro.apa= 1g/cm³
m,apa= roxv=30g
se aproximeaza (mc)sol=(mc)apa= 30gx4,18j/gxgrad=125,4j/grd
Cvas=50x4,18j/grd=209j/grd
Q= (209+125,4)20 J=6688J
niu, sare= m/miu=3/148g/mol=0,02mol
ΔHdiz= - Q/niu=-6688/0,02mol= - 334400j/mol=-334kj/mol
Explicație: