Răspuns:
Explicație pas cu pas:
a)
3x²-x-2=0
x1,2=1±√1+24/6=1±5/6 x1=1 x2=-4/6=-2/3
3x²-x-2==(x-x1)(x-x2)=(x-1)(3x+2)
b) x≠{-2/3,-1/2,1}
2x²-x-1=0
x1,2=1±√1+8/4=1±3/4 x1=1 x2=-1/2
2x²-x-1=(x-1)(2x+1)
E(x)=(x-1)(3x+2)/(x-1)(2x+1) : (2x+1+x+1)/(2x+1)=(3x+2)/(2x+1)·(2x+1)/(3x+2)=1