II.
ms= 400g, c% = 35%
c% = mdx10/ms
=> md = msxc%/100 = 400x35/100 = 140 g AgNO3
M.AgNO3 = 108+14+3x16 = 170 g/mol
M.HNO3 = 1+14+3x16 = 63 g/mol
140g m g
AgNO3 + HCl --> AgCl + HNO3
170 63
=> m = 140x63/170 = 51,9 g HNO3
III.
100% .................. 155g CaCO3 impur
60% ................ m.p. = 93 g CaCO3 pur
M.CaCO3 = 40+12+3x16 = 100 g/mol
M.CO2 = 12+2x16 = 44 g/mol
93g m g
CacO3 ---> CaO + CO2
100 44
=> 93x44/100 = 40,92 g CO2
