Răspuns :

Vitasea77id

Explicație pas cu pas:

[tex]q = \frac{2x + 1}{x + 2} = \frac{3x + 4}{2x + 1} [/tex]

=>

[tex] {(2x + 1)}^{2} = (x + 2)(3x + 4) \: \: \: \: \: [/tex]

[tex]4 {x}^{2} + 4x + 1 = 3 {x}^{2} + 10x + 8[/tex]

[tex] {x}^{2} - 6x - 7 = 0[/tex]

Relatii Vieta =>

[tex]x = - 1 \: \\ x = 7[/tex]

Zenk110id

Explicație pas cu pas:

q=

x+2

2x+1

=

2x+1

3x+4

=>

{(2x + 1)}^{2} = (x + 2)(3x + 4) \: \: \: \: \:(2x+1)

2

=(x+2)(3x+4)

4 {x}^{2} + 4x + 1 = 3 {x}^{2} + 10x + 84x

2

+4x+1=3x

2

+10x+8

{x}^{2} - 6x - 7 = 0x

2

−6x−7=0

Relatii Vieta =>

\begin{gathered}x = - 1 \: \\ x = 7\end{gathered}

x=−1

x=7

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