C3H8O --H+--> C3H6 + H2O
n kmoli 120 kg
C3H6 + H2O --H+--> C3H8O, 2-propanol
1 60
=> n = 1x120/60 = 2 kmoli C3H6
aplicam legea gazelor ideale
PV = nRT => V = nRT/P = 2x0,082(273+127)/3
= 21,87 m3 propena
