Iulyaciumacencoid
a fost răspuns

Efectuati:
[tex]( {x}^{2} + {2y}^{ - 2} ) {}^{3} [/tex]
[tex](a {}^{ - 3} + ab {}^{2} ) {}^{3} [/tex]
[tex](2.5z + 3tz {}^{2} ) {}^{3} [/tex]
[tex](a {}^{3} b + 0.1b) {}^{3} [/tex]
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Răspuns :

Mosthatedjjoid

a)

[tex](x {}^{2} - 2 \times \frac{1}{y {}^{2} } ) {}^{3} [/tex]

[tex](x {}^{2} - \frac{2}{y {}^{2} } ) {}^{3} [/tex]

[tex]( \frac{x {}^{2}y {}^{2} - 2}{y {}^{2} } ) {}^{3} [/tex]

[tex]( \frac{x {}^{2}y {}^{2} - 2 }{y {}^{6} } ) {}^{3} [/tex]

[tex] \frac{x {}^{6}y {}^{6} - 6x {}^{4} + 12x {}^{2} y {}^{2} - 8 }{y {}^{6} } [/tex]

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