Răspuns:
[tex] \sqrt{2} \sqrt{3} + \sqrt{6} = \\ \sqrt{6} + \sqrt{6} = 2 \sqrt{6} [/tex]
[tex] \sqrt{3 \times 15} - \sqrt{75} = \\ \sqrt{45} - 5 \sqrt{3} = 3 \sqrt{5 } - 5 \sqrt{3} [/tex]
[tex]13 \times 15 - \sqrt{15} = 195 - \sqrt{15} [/tex]
[tex] \sqrt{5} - \sqrt{10 \div 12} = \\ \sqrt{5} - \sqrt{ \frac{10}{12} } = \\ \sqrt{5 } - \sqrt{ \frac{5}{6} } = \sqrt{5} - \frac{ \sqrt{30} }{6} [/tex]
Sper ca te am ajutat!!!
