Răspuns:
A,Mg=24g/mol
miu,MgSO4=120g/mol
-calculez masa de Mg PUR de puritate 90%
p=m,px10/m,i----> m,p= 200x90/100g=180g
-calculez, din ecuatia chimica, masa de sare care se obtine
1mol,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,1mol sau,in grame
Mg + H2SO4-----> MgSO4 + H2
24g..................................120g
180g...............................x
x=m,teoretica= 900g
m,practic=900g
eta= m,practicx100/m,teoretic=900x100/900=100%
Explicație:
