Răspuns:
2Mg + O2---> 2MgO
a
MgO + H2O---> Mg(OH)2
b
MgCO3----> MgO + CO2↑
c
2NaHCO3----> Na2CO3 + H2O+ CO2↑
r.a. Na:H:C:O=1:1:1: 3
r.m 23 : 1 : 12 : 3x16
miu= 23+1+12+48->84g/mol
84g bicarbonat......23gNa....1gH....12gC......48gO
100g..........................x.............y........z.............t
x=27,4%Na
y=1,2% H
z=14,3%C
t=57,1% O
x+ y + z +t=100g
Explicație: