Răspuns :

Răspuns:

[tex]a) {2}^{10} \times {4}^{3} \div {8}^{2} = \\ {2}^{10} \times ( {2}^{2} ) {}^{ 3} \div ( {2}^{3} ) {}^{2} = \\ {2}^{10} \times {2}^{6} \div {2}^{6} = \\ {2}^{16} \div {2}^{6} = {2}^{10} \\ \\ b) {9}^{10} \times {3}^{7} \div {27}^{2} = \\ ({3}^{2} ) {}^{10} \times {3}^{7} \div ({3}^{3} ) {}^{2} = \\ {3}^{20} \times {3}^{7} \div {3}^{6} = \\ {3}^{27} \div {3}^{6} = {3}^{21} [/tex]

sper că te-am ajutat!