9.a)[tex](2x-1)^{2} =(2x)^{2} -2* 2x * 1+1^{2} =4x^{2} -4x+1[/tex]
b)[tex](2x+3)^{2} =(2x)^{2} +2 * 2x * 3+3^{2} =4x^{2} + 12x +9[/tex]
c)[tex](4x+1)^{2} =(4x)^{2} +2 * 4x * 1+1^{2} =16x^{2} +8x+1[/tex]
d)[tex](2x-1)*(2x+1)=(2x)^{2} -1^{2} =4x^{2} -1^{2} =4x^{2} -1[/tex]
e)[tex](3x+2)*(3x-2)=(3x)^{2} -2^{2} =9x^{2} -4[/tex]
f)[tex](x-\sqrt{3} )^{2} =x^{2} -2x\sqrt{3} +\sqrt{3} ^{2} =x^{2} -2\sqrt{3} x +3[/tex]
g)[tex](x\sqrt{2} -1)^{2} =(\sqrt{2} x-1)^{2} =2x^{2} -2\sqrt{2} x+1[/tex]
h)[tex](2x+\sqrt{2})^{2} =(2x)^{2} +2*2x\sqrt{2} +\sqrt{2} ^{2} =4x^{2} +4\sqrt{2} x+2[/tex]
10.a)[tex](2+\sqrt{3} )^{2} =4+4\sqrt{3} +3=7+4\sqrt{3}[/tex]
b)[tex](2\sqrt{3} -1)^{2} =12-4\sqrt{3} +1=13-4\sqrt{3}[/tex]
c)[tex](\sqrt{3} +1)*(\sqrt{3} -1)=3-1=2[/tex]
d)[tex](\sqrt{3} -\sqrt{2} )*(\sqrt{3} +\sqrt{2} )=3-2=1[/tex]
e)[tex](\sqrt{5} +2)*(\sqrt{5} -2)=5-4=1[/tex]
f)[tex](3\sqrt{2} -2\sqrt{3} )^{2} =18-12\sqrt{6} +12=30-12\sqrt{6}[/tex]
g)[tex](3\sqrt{3} +2\sqrt{2} )^{2} =27+12\sqrt{6} +8=35+12\sqrt{6}[/tex]
h)[tex](3\sqrt{2} -2\sqrt{3} )*(3\sqrt{2} +2\sqrt{3} )=9*2-4*3=18-12=6[/tex]
Sper ca te-am ajutat!Spor!
