[tex]a = 4 + |3 \sqrt{2} - 4| = 4 + 3 \sqrt{2} - 4 = 3 \sqrt{2} [/tex]
[tex]b = \sqrt{20} [/tex]
[tex]a = 3 \sqrt{2} = > (3 \sqrt{2} ) {}^{2} = 9 \times 2 = 18[/tex]
[tex]b = \sqrt{20} = > ( \sqrt{20} ) {}^{2} = 20[/tex]
[tex]18 < 20 = > a < b[/tex]
