Răspuns :
[tex]\it 2X=\begin{pmatrix}7&4\\ 6&3 \end{pmatrix}-\begin{pmatrix}1&0\\ 2&1\end{pmatrix} \Rightarrow 2X=\begin{pmatrix}6&4\\ 4&2 \end{pmatrix} \Rightarrow 2X=2\cdot \begin{pmatrix}3&2\\ 2&1 \end{pmatrix} \Rightarrow X=\begin{pmatrix}3&2\\ 2&1 \end{pmatrix}[/tex]