Răspuns :

Stefanemanueltoyoz5iid

Răspuns:

[tex]x = 6 {}^{2} \div 3 {}^{2} - 3 \\ x = 36 \div 9 - 3 \\ x = 4 - 3 \\ x = 1[/tex]

[tex]y = (4 {}^{3} - 2 {}^{3} ) \div 2 {}^{3} \\ y = (64 - 8) \div 8 \\ y = 56 \div 8 \\ y = 7[/tex]

=> x<y

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