Răspuns:
1molC..........12g
X................7,02g
x= niu= 0,585molC
sau niu=m/A,C
1mol C...........6,023x10²³atomi
0,585mol...............x
x=N=3,52X10²³atomi
sau N=niuxN,A (numarul lui Avogadro)
niu= N/N,A=7,56X10²²/6,023x10²³ mol=0,1255molCF4
m=niuxM, unde M,CF4=88g/mol m=0,1255x88g=11,04gCF4
88gCF4...........76gF
11,04g..................X
X=9,53gF
Explicație:
