Răspuns:
[tex]\sqrt{5^{2}*2^{3}} =10\sqrt{2}[/tex]
[tex]\sqrt{6+\frac{1}{4} } =\sqrt{\frac{25}{4} } =\frac{5}{2}[/tex]
[tex]\sqrt{3^{2}+4^{2} } =\sqrt{9+16} =\sqrt{25} =5[/tex]
[tex]\sqrt{5\frac{1}{9} } =\sqrt{\frac{46}{9} } =\frac{\sqrt{46}}{3}[/tex]
[tex]\sqrt{3^{4}*5^{2}} =45[/tex]
[tex]\sqrt{11+\frac{1}{9} }=\sqrt{\frac{100}{9}}=\frac{10}{3}[/tex]
[tex]\sqrt{16+\frac{1}{5} } =\sqrt{\frac{81}{5} } =\frac{9\sqrt{5} }{5}[/tex]
A={[tex]10\sqrt{2} , \frac{5}{2}, 5, \frac{\sqrt{46}}{3}, 45, \frac{10}{3}, \frac{9\sqrt{5} }{5}[/tex]}
A∩N={5, 45}
A∩Q\Z={[tex]\frac{5}{2} , \frac{10}{3}[/tex]}
A∩R\Q={[tex]10\sqrt{2} , \frac{\sqrt{46}}{3} , \frac{9\sqrt{5} }{5}[/tex]}
Explicație pas cu pas:
