[tex]3a + \frac{24}{17} - 41 = \\ 3a + 1 \frac{7}{24} - 41 = \\ 3a - 40 \frac{7}{24} = \\ 3a = 40 \frac{7}{24} \\ 3a = \frac{967}{24} \\ a = \frac{967}{24 \times 3} \\ a = \frac{967}{72} \\ a = 13 \frac{5}{9} [/tex]
