Răspuns :
[tex]\it \Big(\dfrac{^{2)}1}{\ 2}- \dfrac{3}{4}\Big)^3 : \Big(- \dfrac{1}{4} \Big)^2 -0,5= \dfrac{x}{16} \Rightarrow \Big(- \dfrac{1}{4}\Big )^3:\Big(- \dfrac{1}{4} \Big)^2- \dfrac{1}{2} =\dfrac{x}{16} \Rightarrow\\ \\ \\ \Rightarrow- \dfrac{1}{4} - \dfrac{1}{2}= \dfrac{x}{16} |_{\cdot16} \Rightarrow-4-8=x \Rightarrow x=-12[/tex]