Răspuns :
[tex]\left(x+2\right)^2-\left(x-1\right)^2[/tex]
[tex]= \left(x+2\right)^2:\quad x^2+4x+4[/tex]
[tex]=x^2+4x+4-\left(x-1\right)^2[/tex]
[tex]= \left(x-1\right)^2:\quad x^2-2x+1[/tex]
[tex]= -\left(x^2-2x+1\right)[/tex]
[tex]= \quad -x^2+2x-1[/tex]
[tex]=x^2+4x+4-x^2+2x-1[/tex]
[tex]=x^2-x^2+4x+2x+4-1[/tex]
[tex]=4x+2x+4-1[/tex]
[tex]=6x+4-1\\[/tex]
[tex]=6x+3[/tex]
Sper că te-am ajutat!
Succes!