Răspuns :

a)

[tex]\bf 5^{1256}+5^{1257}+3\cdot5^{1255}=[/tex]

[tex]\bf 5^{1255}\cdot(5^{1}+5^{2}+3\cdot5^{0})=[/tex]

[tex]\bf 5^{1255}\cdot(5^{1}+25+3)=[/tex]

[tex]\boxed{\bf 5^{1255}\cdot 33}[/tex]

b)

[tex]\bf 2^{102}-2^{101}-2^{100}=[/tex]

[tex]\bf 2^{100}\cdot(2^{2}-2^{1}-2^{0}) =[/tex]

[tex]\bf 2^{100}\cdot(4-2-1) =[/tex]

[tex]\bf 2^{100}\cdot 1 = \boxed{\bf 2^{100}}[/tex]

c)

[tex]\bf (3^{75}-3^{74}-3^{73}):(5\cdot 3^{72})=[/tex]

[tex]\bf 3^{73}(3^{2}-3^{1}-3^{0}):(5 \cdot 3^{72})=[/tex]

[tex]\bf 3^{73}(9-3-1):(5 \cdot 3^{72})=[/tex]

[tex]\bf 3^{73}\cdot 5 : 5 \cdot 3^{72}=[/tex]

[tex]\bf 3^{73-72}=3^{1}=\boxed{\bf 3}[/tex]

d)

[tex]\bf 5^{2n+1}-4\cdot 25^{n}- 5^{2n}=[/tex]

[tex]\bf 5^{2n+1}-4\cdot 5^{2n}- 5^{2n}=[/tex]

[tex]\bf 5^{2n}\cdot(5^{1}-4\cdot 5^{0}- 5^{0})=[/tex]

[tex]\bf 5^{2n}\cdot(5-4-1)=[/tex]

[tex]\bf 5^{2n}\cdot 0 =\boxed{\bf 0}[/tex]

e)

[tex]\bf (7^{100}-6\cdot7^{99}+11^{110}: 121^{55}-7^{99})^{100}=[/tex]

[tex]\bf (7^{100}-6\cdot7^{99}+11^{110}: 11^{110}-7^{99})^{100}=[/tex]

[tex]\bf (7^{100}-6\cdot7^{99}+1-7^{99})^{100}=[/tex]

[tex]\bf (7^{100}-7\cdot7^{99}+1)^{100}=[/tex]

[tex]\bf (7^{100}-7^{100}+1)^{100}=[/tex]

[tex]\bf 1^{100}=\boxed{\bf 1}[/tex]

f)

[tex]\bf 2^{n+2}\cdot3^{n+1}-6^{n}=[/tex]

[tex]\bf 2^{n+2}\cdot3^{n+1}-2^{n}\cdot3^{n}=[/tex]

[tex]\bf 2^{n}\cdot3^{n}\cdot(2^{2}\cdot3^{1}-2^{0}\cdot3^{0})=[/tex]

[tex]\bf 2^{n}\cdot3^{n}\cdot(4\cdot3-1\cdot1)=[/tex]

[tex]\bf 2^{n}\cdot3^{n}\cdot(12-1)=[/tex]

[tex]\boxed{\bf 2^{n}\cdot3^{n}\cdot 11}[/tex]

Explicație pas cu pas:

Am atasat rezolvarea ... .....

Vezi imaginea LITHOPSOPTICA
Vezi imaginea LITHOPSOPTICA