Răspuns :

Răspuns:

[tex]x^{2}[/tex]-7x+12=0 => a=1, b= -7, c= 12

=> delta = [tex]b^{2}[/tex]-4*(a*c) => delta = 49-48 => delta = 1

=>

[tex]x_{1}[/tex]= (-b + [tex]\sqrt{delta\\}[/tex]) /2*a =>

[tex]x_{2}[/tex]= (-b - [tex]\sqrt{delta\\}[/tex]) / 2*a =>

[tex]x^{2}[/tex]-7x+12= (x-4)(x-3)

E = x²-7x+12

= x²-3x-4x+12

= x(x-3)-4(x-3)

= (x-3)(x-4)