Notez [tex]\frac{x+1}{x-1}[/tex] cu t
=>t+1/t=25/12
t+1/t-25/12=0
12[tex]t^{2}[/tex]+12-25t/12t=0
12[tex]t^{2}[/tex]+12-25t=0
12[tex]t^{2}[/tex]-9t-16t=12=0
3t(4t-3)-4(4t-3)=0
(4t-3)(3t-4)=0
4t-3=0 => t=3/4
3t-4=0 =>t=4/3
x+1/x-1=3/4 =>
4x+4=3x-3
4x-3x=-3-4
x=-7
x-1/x+1=4/3
x=7
