Răspuns:
se aplica relatia niu=m/M
a. M,CaO=56g/mol niu=5,6/56mol=0,1mol
b. M,H2SO4=98g/mol niu=980/98mol=10mol
c.M,H2O=18g/mol niu= 3600/18mol=200mol
d.M,Al(OH)3=78g/mol niu=156/78mol=2mol
SE aplica relatia m= niuxM
a. M,HNO3=63g/mol m=6x63g=378g
b. M,MgO=40g/mol m= 3500x40g=140000g
c. M,CO2=44g/mol m= 0,2x44g= 8,8g
d .M,NaOH=40g/mol m= 1x40g=40g
Explicație:
