Răspuns:
Explicație:
1.
a. AlCl3
b. Ca(OH)2
d. BaO
e. K2CO3
f. Na2SO3
2.
m= n . M
a. MNa2CO3= 2 . 23 + 12 + 3 . 16=106-------> 106g/moli
m= 10moli . 106g/moli=1060 g Na2CO3
b. MCaO= 40 +16=56-------> 56g/moli
m= 3moli . 56g/moli=168 g CaO
3.
n = m : M
a. MMgCl2= 24 + 2 . 35,5=95------> 95g/moli
n= 190g : 95g/moli=2moli MgCl2
b. MCa(OH)2=40 + 2.16 + 2=74------> 74g/moli
n= 370g : 74g/moli = 5 moli Ca(OH)2
4.
a.
1mol NH3-----------6,023.10²³molecule
1,5 moli------------------------x
x= 1,5 . 6,023.10²³molecule=9,0345.10²³molecule NH3
b.
1mol SO3---------6,023.10²³molecule
2moli---------------------------y
y= 2 . 6,023.10²³molecule=12,046 .10²³molecule SO3
5.
a.
SiCl4
r.a.= 1 : 4
r.m. = 28 : 4 . 35,5 =28 : 142 se simplif . cu 2
=14 : 71
b.
KClO3
r.a.= 1 : 1 : 3
r.m.= 39 : 35,5 : 3 . 16
= 39 : 35,5 : 48
c.
comp. proc . la SO2
MSO2= 32 + 2 . 16=64------> 64g/moli
64g SO2-----32gS--------32gO
100g---------------x------------y
x= 100 . 32 : 64=50% S
y= 50% O
6.
a. MCa(OH)2= 40 + 2 .16 + 2=74-------> 74g/moli
74g Ca(OH)2-----------40g Ca
xg----------------------------80gCa
x= 74 . 80 : 40=148 g Ca(OH)2
b
74g Ca(OH)2--------32gO
yg-------------------------64gO
Y= 74 . 64 : 32=148 g Ca(OH)2
