in triunghiul dreptunghic abc , dreptungic in a , inaltimea Ad , aflati laturile triunghiului in fiecare caz ! va rogggggg ​

In Triunghiul Dreptunghic Abc Dreptungic In A Inaltimea Ad Aflati Laturile Triunghiului In Fiecare Caz Va Rogggggg class=

Răspuns :

Răspuns:

Explicație pas cu pas:

1) AB²=BD*BC

BC=AB²/BD = 4²/2=16/2=8cm

AB²+AC²=BC²

AC=√(BC²-AB²)=√(8²-4²)=√(64-16)=√(48)=4√3cm

AB=4cm,  AC=4√3cm, BC=8cm

2) AC²=CD*BC

BC=AC²/CD = 6²/4=36/4=9cm

AB²+AC²=BC²

AB=√(BC²-AC²)=√(9²-6²)=√(81-36)=√(45)=3√5cm

AB=3√5cm,  AC=6cm, BC=9cm

3) BC=CD+BD=4+5=9cm

AC²=CD*BC

AC=√(CD*BC)=√(4*9)=√36=6cm

AB²=BD*BC

AB=√(BD*BC)=√(5*9)=√45=3√5cm

AB=3√5cm,  AC=6cm, BC=9cm

4) AB²=AD²+BD²

AB=√(AD²+BD²)=√[(3√5)² + 5²]=√(45 + 25)=√80=4√5cm

AB²=BD*BC

BC=AB²/BD = (4√5)²/5=80/5=16cm

BC²=AB²+AC²

AC=√(BC²-AB²)=√[16² - (4√5)²]=√(256-80)=√176=4√11cm

AB=4√5cm,  AC=4√11cm, BC=16cm

5) AB²+AC²=BC²

AB=√(BC²-AC²)=√(13²-5²)=√(169-25)=√(144)=12cm

AB=12cm,  AC=5cm, BC=13cm

6) AB²+AC²=BC²

AB=√(BC²-AC²)=√[6²-(4√2)²]=√(36-32)=√(4)=2cm

AB=2cm,  AC=4√2cm, BC=6cm

7) AB²=AD²+BD²

BD=√(AB²-AD²)=√(3² - 2,4²]=√(9 -- 5,76)=√3,24=1,8m

AB²=BD*BC

BC=AB²/BD = 3²/1,8=9/1,8=5m

BC²=AB²+AC²

AC=√(BC²-AB²)=√(5² - 3²]=√(25-9)=√16=4m

AB=3m,  AC=4m, BC=5m

8) AC²=CD*BC

AC=√(CD*BC) =√(5,4*15) =√81 =9m

AB²+AC²=BC²

AB=√(BC²-AC²)=√(15²-9²)=√(225-81)=√(144)=12m

AB=12m,  AC=9m, BC=15m

9) AC²=AD²+DC²

AC=√(AD²+DC²)=√[(3√3)² + 9²]=√(27 + 81)=√108=6√3m

AC²=DC*BC

BC=AC²/DC = (6√3)²/9=108/9=12m

BC²=AB²+AC²

AB=√(BC²-AC²)=√[12² - (6√3)²]=√(144-108)=√36=6m

AB=6m,  AC=6√3m, BC=12m