Răspuns:
8, 18, 40
Explicație pas cu pas:
notam cu a, b, c numerele
a+b+c = 66
b= c:2-2 => 2b = c -4 => c = 2b+4
b = 2+2a => 2a = b-2 => a = b:2-1
inlocuim in prima relatie
b:2 -1 +b +2b+4 = 66 /*2
b -2 +2b +4b +8 = 132
7b +6 = 132 /-6
7b = 126 /:7
b = 18
c = 18*2+4 => c = 40
a = 18:2-1 => a = 9-1 =>a =8
Verificare: 8+18+40 = 66 (adevarat)
a-primul nr
b-al doilea nr
c-al treilea nr
b=(c÷2)-2
b=(a·2)+2
=>(c÷2)-2=2a+2 =>2a=(c÷2)-4=>a=(c÷2-4)÷2
a+b+c=66=>[(c÷2-4)÷2] + (c÷2-2) + c =66 =>
[tex]\frac{\frac{c}{2}-4 }{2} + \frac{c}{2} -2+c=66\\ \\\frac{c-8}{4}+\frac{c-4}{2}+c=66\\ \\\frac{c-8}{4} +\frac{2c-8}{4}+\frac{4c}{4}=66x4\\\\=>c-8+2c-8+4c=264\\=>7c-16=264\\=>7c=280=>c=40[/tex]
=>b=40÷2-2=>b=18
=>a=(40÷2-4)÷2=>a=8
