Răspuns:
Explicație pas cu pas:
Buna dimineata!
a) (2x³y)³×((2x³y)² = (2x³y)³⁺²=(2x³y)⁵=2⁵x¹⁵y⁵
b) (-√3ab)⁵×(√3ab)³= (-1)⁵(√3ab)⁵⁺³= -(√3ab)⁸= -(√3)⁸a⁸b⁸= -81a⁸b⁸
c)(2/3 × xy²z)⁴× (2/3 × xy²z) = (2/3 × xy²z)⁴⁺¹ = (2/3 × xy²z)⁵ = (2/3)⁵× (xy²z)⁵ = 2⁵/5⁵ × x⁵y¹⁰z⁵ =32/3125 × x⁵y¹⁰z⁵
d) [(x³y²z⁵)³]⁶= (x⁹y⁶z¹⁵)⁶ = x⁵⁴y³⁶z⁹⁰
e) [(-2ab³)³]²= (-8a³b⁹)²=64a⁶b¹⁸
f) 3(ab)³ × (a²b³)⁵ = 3×a³b³ × a¹⁰b¹⁵ = 3×a³⁺¹⁰× b³⁺¹⁵ =3a¹³b¹⁸
g) (-√2x²yz³)⁴× (3xy²)³ × (-1/3 × yz)²= 4x⁸y⁴z¹² × 27x³y⁶ × (1/9×y²z²) = 4 × 27 × 1/9 × x⁸⁺³ y⁴⁺⁶⁺²z¹²⁺² = 4 × 3 × x¹¹y¹²z¹⁷
Succes!
