Răspuns :

Teodorab82id

Fie nr a, a+1, a+2, a+3, a+4, a+5, a+6.

a+a+1+a+2+a+3+a+4+a+5+a+6=-7

7×a +(1+2+3+4+5+6)=-7

7×a +21=-7

7×a=-7-21=-28

a=-28:7=-4

Deci nr sunt -4,-3,-2,-1,0,1,2

Răspuns:

x+x+1+x+2+x+3+x+4+x+5+x+6=-7

7x+21=-7

7x=-28

x=-4

S={-4, -3, -2, -1, 0, 1, 2}

Explicație pas cu pas:

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