Răspuns:
Explicație pas cu pas:
10.
a+b+c=1032
b=3a
c=a/2+60
a+3a+a/2+60=1032
a+3a+a/2=972
2a+6a+a=1944
9a=1944, a=1944/9=216
b=3*216=648
c=216/2+60=108+60=168
12.
patru numere consecutive pot fi de forma x, x+1, x+2, x+3
x+x+1+x+2+x+3=110
4x+6=110
4x=104, x=26