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Lazarelias2007id

Răspuns:

1+2+3+4+.....+11+m=70+2×9

[(1+2+3+4+....+10)+11]+m=70+18

[(1+2+3+4+.....+7+8+9+10)+11]+m=88

1+10=11

2+9=11

3+8=11

4+7=11

1.....10-10 nr

10÷2=5 perechi de nr.

5×11=55

(55+11)+m=88

=66+m=88

m=88-66

m=22

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