Răspuns :
AC_Ipotenuza
AB, BC- catete
AC=10
AB=6
Pitagora
AC^2=AB^2+BC^2
10^2=6^2+BC^2
BC^2=100-36
BC^2=64
BC= radical din 64
BC=8
AB, BC- catete
AC=10
AB=6
Pitagora
AC^2=AB^2+BC^2
10^2=6^2+BC^2
BC^2=100-36
BC^2=64
BC= radical din 64
BC=8
Se aplica teorema lui Pitagora:
[tex]AC^{2} = BC^{2} + BA^{2} => BC^{2} = AC^{2} - BA^{2} [/tex][tex]=> BC^{2} = \sqrt{100-36} =64 => BC= 8[/tex]
[tex]AC^{2} = BC^{2} + BA^{2} => BC^{2} = AC^{2} - BA^{2} [/tex][tex]=> BC^{2} = \sqrt{100-36} =64 => BC= 8[/tex]