Răspuns :

Alexutzuu10id
Cred ca trebuia concentratia molara a solutiei*

[tex]n= \frac{m}{M}= \frac{400}{40}=10 [/tex] moli NaOH

[tex]c_{M} = \frac{n}{V_{s}} [/tex] = [tex] \frac{10}{5} = 2M[/tex] ( sau 2 moli / L )

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