[tex] \frac{3x-7}{x+5}= \frac{x-3}{x+2} \\ (3x-7)(x+2)=(x+5)(x-3) \\ 3 x^{2} +6x-7x-14= x^{2} -3x+5x-15 \\ 2 x^{2} -3x+1=0 \\ delta= b^{2} -4ac=9-8=1 \\ x1= \frac{-b+ \sqrt{delta} }{2a} = \frac{3+1}{4} =1 \\ x2= \frac{-b- \sqrt{delta} }{2a} = \frac{1}{2} [/tex]