Răspuns :
atim ca axb=18
axc=10
ax(b+c):7=
=(axb+axc):7
=(18+10):7
=28:7
=4
ax(b-c):8=
(axb-axc):8=
=(18-10):8
=8:8
=1
axc=10
ax(b+c):7=
=(axb+axc):7
=(18+10):7
=28:7
=4
ax(b-c):8=
(axb-axc):8=
=(18-10):8
=8:8
=1
ab=18
ac=10 prin adunare ne da
ab+ac=28
a(b+c)=28
a(b+c):7=28:7=4
a(b-c):8=(ab-ac);8=(18-10):8=8:8=1
ac=10 prin adunare ne da
ab+ac=28
a(b+c)=28
a(b+c):7=28:7=4
a(b-c):8=(ab-ac);8=(18-10):8=8:8=1