Răspuns :
Fie a -I nr. iar b-II nr
avem ca M a=a+b/2
Iar M g=√a+b
DEci
Ma=26= 16+36/2 = 52/2=26
Mg=√ 16*36 =√ 576=24
R/s : a=16 b =36
avem ca M a=a+b/2
Iar M g=√a+b
DEci
Ma=26= 16+36/2 = 52/2=26
Mg=√ 16*36 =√ 576=24
R/s : a=16 b =36
ma=(a+b)/2=26
a+b=2*26
a+b= 52
a=52-b
√ab=24
ab= 576
a+b=52
a=52-b
b(52-b)=576
52b -b² =576
52b-b² -576 =0 |-1
b² -52b +576 =0
a=1
b = -52
c= 576
Δ = 2704 -4*576 =2704-2304= 400
x1;x2= (52 + /- √400)/2= (52 +/- 20)/2
x1= (52+20)/2= 72/2=36
x2= (52-20)/2= 32/2= 16
b² -52 +576=0
(x-36)(x-16)=0
x-36=0 ∧ x-16=0
x=36 x=16
b=36 ∧ a=16
a+b=2*26
a+b= 52
a=52-b
√ab=24
ab= 576
a+b=52
a=52-b
b(52-b)=576
52b -b² =576
52b-b² -576 =0 |-1
b² -52b +576 =0
a=1
b = -52
c= 576
Δ = 2704 -4*576 =2704-2304= 400
x1;x2= (52 + /- √400)/2= (52 +/- 20)/2
x1= (52+20)/2= 72/2=36
x2= (52-20)/2= 32/2= 16
b² -52 +576=0
(x-36)(x-16)=0
x-36=0 ∧ x-16=0
x=36 x=16
b=36 ∧ a=16