[tex]( \frac{ 2x^{2} -7x-17}{(x-3)(x+7)} - \frac{x+1}{x-7}) (x-3)(x+3)= \frac{2 x^{2} -7x-17-(x-3)(x+1)}{(x-3)(x+7)} (x-3)(x+3)[/tex]=
[tex] \frac{2 x^{2} -7x-17- x^{2} +3x-x+3}{(x-3)(x+7)} (x-3)(x+3)= \frac{ x^{2} -5x-14}{x+7} (x+3)= [/tex]
[tex] \frac{(x+7)(x+2)}{x+7} (x+3)=(x+2)(x+3)[/tex]
