Răspuns :

Miky93id
x+y=56
y+z=88
x+z=80

2x+2y+2z=56+80+88
2(x+y+z)=224
x+y+z=112

z=112-56
z=56

x=112-88
x=24

y=112-80
y=32
Ctinamaria31xxxid
x+y=56

y+z=88=>y=88-z
x+z=80=> x=80-z

80-z+88-z=56
168-2z=56
168-56=2z
112=2z
z=112:2
z=56

y=88-56
y=32

x=80-56
x=24

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